Solution

Here we notice that \(11-7=4,9-5=4\) and \(6-2=4\). This means we have to find out the values that is four less than the common multiple of 11,9 , and 6 .

The LCM of \(11, 9\) and \(6\) is \(198\).

So the numbers that fulfill the condition can be written as \(198 x-4\), where \(x\) is a positive integer.

Here the value is a three-digit integer.

So, \(x\) will be \(1,2,3,4\) and \(5\) , which gives the values \(194,392,590,788\), and \(986\) respectively.

We have 5 values.

So the answer will be \(5\).

• This reply was modified 1 year, 4 months ago by Arisha Roy.
• This reply was modified 1 year, 4 months ago by Arisha Roy.