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Tagged: Plane geometry
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Aritra.
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- June 6, 2019 at 4:47 pm #28915
Soumyadeep mandalParticipantSuppose we have to cover the xy plane with identical tiles such that no two tiles overlap and no gap is left between the tiles. Suppose that we can chose the tiles of the following shapes: equilateral triangle, square, regular pentagon, regular hexagon. Then the tilings can be done with the tiles of
A) all four shapes
B) exactly three of the four shapes
C) exactly two of the four shapes
D) exactly one of the four shapes
I am not able to comprehend the question please help....
June 7, 2019 at 5:58 pm #29006AritraModeratorif you tile the plane by congruent regular polygons, there must be nn polygons meeting at each vertex. Thus the interior angles of each polygon must be 2π/n, for some positive integer n .
now see that for n≤6 the angle is greater than π/3 .
but for , n>6 the polygons would need to have angles less than π/3, which is impossible.
but when n= 5 then internal angle is 108 which doesnot divide 360 so pentagon is not possible , option a is correct
June 8, 2019 at 11:13 am #29062Soumyadeep mandalParticipantOk... so a pentagon is not possible and the other shapes are possible right .
? Thank you...
June 8, 2019 at 12:39 pm #29064AritraModeratoryes, even except those three no tiling is possible
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