New Home › Forums › Math Olympiad - IOQM › Double derivative
Tagged: Double derivative
Double derivative
It is bounded and converges to 0
$a^x$ grows in a much faster rate than $x^a$
after a very big $n$ $e^{\sqrt{n}}$ will be greater than $(n+1)^{100}$ and then it will converge to $0$
.
.