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If x,y,z are 3 arbitrary positive real numbers such that 6xy+8yz+4zx=9, then what is the Maximum value of xyz?
we know that $\frac{4xy+6yz+8xz}{3}\geq (4xy\times 6yz \times 8xz)^\frac{1}{3}$
use this as a hint....try it
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