Solution:

3 equations will be,

\(y=5.........(i)\)

\(y=1+x........(ii)\)

\(y=1-x ..........(iii)\)

By solving eq(i) and eq(ii) we get, \(y=5, x=4\).

By solving eq(i) and eq(iii) we get, \(y=5, x=-4\).

By solving eq(ii) and eq(iii) we get, \(y=1, x=0\).

We will get a triangle base and height of which will be 8 and 4.

Area will be \(\frac{4 \times 8}{2}=16\)

Solution

Let the original price is \(x\) and price is increased by \(y%\).

So, \( x \times \frac{100+y}{100} \times \frac{100-y}{100}=x \times \frac{84}{100}\)

\(10000-y^2=8400\)

\(y=40\)

By \(40\) percent was the price increased and decreased.

• This reply was modified 1 year, 4 months ago by Arisha Roy.