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LHS=[a^5+b^5+{-(a+b)^5}]/5=-a^4b-2a^3b^2-2a^2b^3-ab^4
and a^3+b^3+c^3-3abc=0 gives (a^3+b^3+c^3)/3=abc
again RHS= [a^2+b^2+{-(a+b)}^2]abc/2=[a^2+b^2+ab]ab{-(a+b)}=-a^4b-2a^3b^2-2a^2b^3-ab^4
here LHS=RHS
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