AMC 8, 2024 Problem Marathon

[vineetachoudharyakshita]

Problem 15

Trivially,

We can think of the smallest three-digit number with distinct digits= 123

Therefore, FLY= 123

8x FLYFLY=BUGBUG
8x 123123= 984984

FLY+BUG= 123+984= 1107 (C)

[Genius Stuff with ujan]

Problem 5 :   we can take some multiples of 6 to find this answer .

6 _we have it's factors :  1*6 and 2*3 and hence we get two possible sums 7 and 5.

12  _ we have it's factors: 1*12, 2*6,3*4 and we get some other sums 8 and 7( as a dice can't show 12 we ain't gonna take that case)

18_ we have it's factors _ 1*18,2*9,3*6 and we get sums 9 only ( as a dice can't show 12 and 9 we aren't taking that case)

We see that we get all the options 5,7,8,9 but not 6 hence we get answer as 6 .

Logic 2 :  if we break 6 into all possible groups of two numbers having sum 6 and multiply each of those cases, we will get a multiple of 6 in none of those cases . Hence the answer is 6 , again.

[Genius Stuff with ujan]

<p style="text-align: left;">Problem 6  : answer is b by using common sense and visualization I think there is no need of explanation in this question. Pardon me if I am wrong .</p>

[vineetachoudharyakshita]

Problem 9

Let red marbles be r
Blue marbles b
Green Marbles g

Hence, r= \frac {g} {2}
b=2g

g=g

3g+ \frac {g} {2}

= 7g/2

Therefore the answer should be a multiple of 7= 28 (E)

[vineetachoudharyakshita]

Problem 10

1.1516x50= 5.758x10= 57.58

338+57.58= 395. 58

Closest integer matching= 399 (A)

[Author]

Posts