AMC 8, 2024 Problem Marathon

[vineetachoudharyakshita]

Problem 12

Let the Guppies in the 1st tank be x

Therefore x+ (x+1)+(x+3)+(x+6)= 4x+10=90
x= 20
Therefore 4th tank Guppies= 20+6=26(E)

[vineetachoudharyakshita]

Problem 8

Total possible ways 8 (Including Repetition)
but $11 and $16 Repeat= 8-2=6 (From the ways we get)

Some are listed below-

((2+3)2)2= 20
2x2x2=8
2x2+3= 7

And so on

Ans) 6(D)

[vineetachoudharyakshita]

Problem 14

Trivially I found the shortest route by following small numbers= 5+2+6+5+10=28(A)

[vineetachoudharyakshita]

Problem 19) Red colour=9
White colour= 6

High top=10
Flat ones= 5

Red high top 10-(White colour whole to be counted to get the least values)
10-6=4

= \frac {4} {15} (C)

[vineetachoudharyakshita]

Problem 21

Well, the answer had to be a multiple of 3= (4-1)x=3x

So either 12 or 24 are possible

I had input the values and got 16:4

3y-3+5:y+3-5= 16:4= 32:8
3y+2:y-2= 16:4= 32:8

32:8 works

Hence answer = 24(E)

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