AMC 8, 2024 Problem Marathon

[vineetachoudharyakshita]

For the original Problem 10 (With a value of 1.515ppm) As per what I remember from the paper,

Answer= 1.515x50=7.575x10=75.75

336+75.75= 413.75 Approx 414 and (B)

[Reyaansh Agrawal]

AMC 8 Solutions:

1. 222222 - 22222 - 2222 - 222 - 22 - 2
Finding the ones digit of this is the same as taking the whole thing mod 10.
That would be equal to 2 - 2 - 2 - 2 - 2 - 2.
This is just -8.
-8 ≡ 2 (mod 10)
Hence the answer would be B) 2.

 

[Reyaansh Agrawal]

2. $\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}$

Simplifying, we get:

$\frac{4}{1} + \frac{10}{4} + \frac{4}{100} $,

which is equal to :

$\frac{654}{100}$

which is C) 6.54

 

[Reyaansh Agrawal]

3. To find the black area, we need to find HIJMLK + ABCGFE

= HIJD - KLMD + ABCD - EFGD

= $7^{2}$ - $4^{2}$ + $10^{2}$ - $9^{2}$

= 49 - 16 + 100 - 81

= 33 + 19

= E) 52

[Reyaansh Agrawal]

4. Adding up all the numbers from 1 to 9, we get 45.

The closest square number that is less than 45 is 36.

Subtracting, we get 9.

Since 9 is the largest number from 1 to 9, the answer is E) 9

[Author]

Posts