AMC 8, 2024 Problem Marathon

[Reyaansh Agrawal]

10. In January 1980, the $CO_{2}$ levels were 338 ppm.

Every year, the $CO_{2}$ levels increased by 1.1516 ppm.

In Jan 2030, would be 338 + 50 $\times$ 1.1516 = 338 + 57.58 = 395.58

In the options, the closest number is 399.

A) 399.

[Manya Lohumi]

Problem - 1

Answer -      222222 - ( 22222 + 2222 + 222 + 22 + 2)

As said in the problem we need to find the ones place number after all the calculation is done . To find that number we will take all the ones place numbers from the numbers  in the brackets

2+2+2+2+2 = 10

We will take the ones place number from the sum . Which is 0.

So 222222 - 0 = 222222

Now take the ones place number from the sum . Which is 2.

So the answer is 2

The number in the ones place after the calculation  222222- ( 22222 + 2222 + 222 + 22 + 2) is 2

Option - (B) - 2

• This reply was modified 1 year, 6 months ago by Manya Lohumi.

[Manya Lohumi]

Problem - 2

Answer -  44/11 +  110/44  +  44/1100

To simplify the question we will simplify the fractions

4/1  +  10/4   +   4/100

4÷1=4

10÷4=2.5

4÷100=0.04

4 + 2.5 + 0.04 = 6.54

Option - (C) - 6.54 - is the answer

 

 

 

[Manya Lohumi]

Problem - 3

Answer -

area of the grey region= BCDMLK - KLMJIH + HIJGFE - AEFC

 

 

Area of square ABCD =10×10=100

Area of square AKLM=9×9=81

Area of square AHIJ =7×7=49

Area of square AEFG=4×4=16

100 - 81 + 49 - 16 = 52

Thus , area of the shaded grey region is 52.

Option - (E) - 52

• This reply was modified 1 year, 6 months ago by Manya Lohumi.
• This reply was modified 1 year, 6 months ago by Manya Lohumi.

[Manya Lohumi]

 

 

 

• This reply was modified 1 year, 6 months ago by Manya Lohumi.

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