Tagged: AMC8
problem - 5
Answer - max possible multiple of 6 by the product of 2 dices = 6×6=36
6×1=6 , 6+1=7
6×2=12 , 6+2=8
6×3=18 , 6+3=9
6×4=24 , 6+4=10
6×5=30 , 6+5=11
6×6=36 , 6+6=12
2×3=6 , 2+3=5 — these are all the possible products of 6 by rolling 2 dices and their sum.
Hence we found that 6 can't be the sum of the 2 numbers rolled because it is not in the table made by us.
Option- ( B )- 6
Problem -6
Answer - I think that to do this problem we just need to visualise and guess the answer which is really simple .
The answer is Option - (B) - P,R,Q,S.
Problem - 8
Answer
MONDAY
$2
TUESDAY
$ 4/5
WEDNESDAY
$8/10/7/8
THURSDAY
$11/16/20/23/14/10
note - all the calculation is without repetition
Option - ( D ) - 6
Problem - 12
Answer - there are 90 guppies in total
let the number of guppies in the first tank be - A
As there is 1 more guppi in the 2nd tank than 1st tank so there are
A+ 1 guppies in the second tank.
As there are 2 more guppies in the 3rd tank than the second tank so there are
A+ 3 guppies in the third tank.
As there are 3 more guppies in the 4th tank than the third tank so there are
A+6 guppies in the 4th tank.
If the sum this information we get that
A+(A+1)+(A+3)+(A+6)= 4 A+10 = 90
So we get that A=20
And as the fourth tank = A+6 = 20+6= 26
So the number of guppies in the 4th tank = 26
Option- (E) - 26
Problem - 14
Answer - the samllest path from A to Z is -
AX+XM+MY+YC+CZ = 5+2+6+5+10 = 28
The answer is -
Option - (A) - 28