Calculus

[Prakash Kapadia]

Let f(x) = 5-4(x-2)^2/3 . Then at x=2, the function f(x)

a) Attains a minimum value

b) Attains a maximum value

c) neither

d)is undefines

 

[Saumik Karfa]

Firstly, The function is not differentiable at $x=2$, So there is no question of maxima minima .

Also if I try to find the extremum points other than $x=2$ then also , there is no such points, as $f '(x) \ne 0$ for all $x$.

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