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sin^5x+cos^3x \leq |sin^5x+cos^3x|
\leq |sin^5x|+|cos^3x|
\leq |sin^2x|+|cos^2x|
=sin^2x+cos^2x
=1
or, sinx and cosx must be both 0 or 1. Putting that in given equation gives sinx=1 or cosx=1.
So, x=\pi/2+2n\pi or, x=2m\pi.