New Home Forums Math Olympiad - IOQM Number Theory Pigeon hole principle

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  • #72816
    Crazy Gamer
    Participant

    can you please solve question number 3 using pigeon hole principle

    #72819
    Saumik Karfa
    Participant

    There are $11$ different remainders when a number is divided by $11$.

    $12$ numbers given.

    Consider $12$ pigeons and $11$ holes. Then there will be at least 2 pigeons in a hole.

    i.e., there will be at least two numbers with same remainder when divided by $11$. Then their difference is divisible by $11$

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