Quadratic Equation

[anjali mangal]

$ x^2 + 5 = 0$

 

[Saumik Karfa]

If you compare this with the general form of a quadratic equation $ax^2+bx+c=0$ then you will get $a=1,b=0,c=5$.

then the discriminant $D=b^2-4ac=0-4\times 1 \times 5=-20 < 0$

then we do not have any real roots of the given equation.

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