GCD and Primes | PRMO 2017 | Question 29

For each positive integer n, consider the highest common factor \(h_n\) of the two numbers n!+1 and (n+1)! for n<100, find the largest value of \(h_n\).

n! +1 is not divisible by 1,2,.....,n (n+1)! divisible by 1,2,....,n then \(hcf \geq (n+1)\) and (n+1)! not divisible by n+2, n+3,...... then hcf= (n+1)

let n=99, 99! +1 and (100)! hcf=100 not possible as 100 |99! and 100 is non prime

let n=97 96! + 1 and 97! both divisible by 97 then hcf=97.

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