Geometry and Trigonometry | PRMO 2019 | Problem 11

How many distinct triangles ABC are there, up to similarity, such that the magnitudes of angle A, B and C in degrees are positive integers and satisfy cosAcosB + sinAsinBsinkC=1 for some positive integer k, where kC does not exceed 360 degrees.

Here cosAcosB+sinAsinBsinkC=1 then cosAcosB+sinAsinB+sinAsinBsinkC-sinAsinB=1 then sinAsinB(sinkC-1)=1-cos(A-B)

Then sinkC-1=0 and cos(A-B)=1 then kC=90 and A=B

Then Number of factors of 90 is 90=(2)(\(3^{2}\))(5) then number of factors=(2)(3)(2)=12 for 6 factor A,B are integers

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