Number of ways of arrangement | PRMO 2017 | Question 10

There are eight rooms on the first floor of a hotel, with four rooms on each side of the corridor, symmetrically situated (that is each room is exactly opposite to one other room). Four guests have to be accommodated in four of the eight rooms (that is one in each) such that no two guests are in adjacent rooms or in opposite rooms, find number of ways can the guests be accommodated.

here there is particular way rooms are arranged with guests

Let 1 g be guest in room 1, 3 g be guest in room 3, 6 g be guest in room 6, 8 g be guest in room 8 then arrangement = 1 g 2 empty 3 g 4 empty

5 empty 6 g 7 empty 8 g arrangement wise

where room 1 and room 5 are opposite and facing each other with room 1 has guest and room 5 empty

room 2 and room 6 are opposite and facing each other with room 2 empty and room 6 has guest

room 3 and room 7 are opposite and facing each other with room 3 has guest and room 7 empty

room 4 and room 8 are opposite and facing each other with room 4 empty and room 8 has guest

here with four guests to be filled in four rooms

which can be arranged in 4! ways

empty and filled rooms can be arranged in 2! ways

required number of ways=\(2 \times 4!\)=48 ways.

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