ABCD is a quadrilateral and P, and Q are mid-points of CD, and AB respectively. Let AP, DQ meet at X, and BP, CQ meet at Y . Prove that area of ADX + area of BCY = area of quadrilateral PXQY
The number of ways in which three non-negative integers \( n_1, n_2, n_3 \) can be chosen such that \( n_1+n_2+n_3 = 10 \) is
(A) 66 (B) 55 (C) \( 10^3 \) (D) \( \dfrac {10!}{3!2!1!} \)