Try this problem from I.S.I. B.Stat Entrance Objective Problem based on Derivative.
If y=\(3^\frac{sinax}{cosbx}\), then \(\frac{dy}{dx}\) is
Equation
Derivative
Algebra
Answer:\(3^\frac{sinax}{cosbx}\frac{acosaxcosbx+bsinaxsinbx}{cos^{2}bx}log3\)
B.Stat Objective Problem 764
Challenges and Thrills of Pre-College Mathematics by University Press
\(y=3^\frac{sinax}{cosbx}\)
or, \(\frac{dy}{dx}\)=\(3^{\frac{sinax}{cosbx}}log_{e}{3}\frac{d}{dx}\frac{sinax}{cosbx}\)
or, \(\frac{dy}{dx}\)=\(3^{\frac{sinax}{cosbx}}log_{e}{3}{\frac{cosbxcosaxa-sinax(-sinbx)b}{cos^{2}bx}}\)
or, \(3^\frac{sinax}{cosbx}\frac{acosaxcosbx+bsinaxsinbx}{cos^{2}bx}log3\)
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