Try this TOMATO problem from I.S.I. B.Stat Entrance Objective Problem based on Equations and roots.
The number of ordered pair of integers (x,y) satisfying the equation \(x^{2}+6x+y^{2}=4\) is
Roots
Integers
Equations
Answer: 4
B.Stat Objective Question 71
Challenges and Thrills of Pre-College Mathematics by University Press
\(x^{2}+6x+y^{2}=4\) gives \((x+3)^{2}\)=13-\(y^{2}\)
for 1st value positive integer of x, we have 1st and 2nd value of y and for 2nd value negative integer of x we have 3rd and 4th value of y
then number of ordered pair is 2+2=4.
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