Try this TOMATO problem from I.S.I. B.Stat Entrance Objective Problem based on Number of divisors and Integer.
The smallest positive integer n with 24 divisors (where 1 and n are also considered divisors of n) is
Number of divisors
Integer
Least positive integer
Answer: 360
B.Stat Objective Question 83
Challenges and Thrills of Pre-College Mathematics by University Press
number of divisors of 420=(2+1)(1+1)(1+1)(1+1)=24
number of divisors of 240=(4+1)(1+1)(1+1)=20
number of divisors of 360=(3+1)(2+1)(1+1)=24 and number of divisors of 480=(5+1)(1+1)(1+1)=24 then required number =360.
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